if one root of equation 2xsq- 8x-m =0is 3/2 find the other root of quadratic equation
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Solution :
Compare 2x² - 8x - m = 0 with
ax² + bx + c = 0 , we get
a = 2 , b = -8 , c = -m,
It is given that 3/2 is one root ,
Let the second root = p
Sum of the roots = - b/a
=> 3/2 + p = - (-8)/2
=> 3/2 + p = 4
=> p = 4 - 3/2
=> p = ( 8 - 3 )/2
=> p = 5/3
Therefore,
second root ( p ) = 5/3
••••
Compare 2x² - 8x - m = 0 with
ax² + bx + c = 0 , we get
a = 2 , b = -8 , c = -m,
It is given that 3/2 is one root ,
Let the second root = p
Sum of the roots = - b/a
=> 3/2 + p = - (-8)/2
=> 3/2 + p = 4
=> p = 4 - 3/2
=> p = ( 8 - 3 )/2
=> p = 5/3
Therefore,
second root ( p ) = 5/3
••••
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