Math, asked by contra02, 7 months ago

If one root of equation 6x2-2x+k-4=0 is reciprocal of other. The value of k is​

Answers

Answered by amansharma264
3

EXPLANATION.

one root of equation

=> 6x² - 2x + k - 4 = 0 is reciprocal of other.

To find value of k.

Let one root of equation = a

Their reciprocal of roots = 1/a

products of zeroes of quadratic equation

=> a X 1/a = c/a

=> 1 = k - 4 / 6

=> 6 = k - 4

=> k = 10

Therefore,

value of k = 10

Similar questions