Question

If one root of equation ax^2+bx+c=0 is 1 and a+b+c=0,what will be the another root

Answer 1

a+b+c=0..........*

ax²+bx+c=0

ax²+bx-a-b=0

a(x²-1)+b(x-1)=0

a(x+1)(x-1)+b(x-1)=0

a(x+1)+b=0

ax+a+b=0

ax+a-a-c=0

ax-c=0

x=c/a

2nd root is c/a