Question

IF ONE ROOT OF Equation is (x-2)(x+3) =0 is 2, then the other root is​

Answer 1

given equation (x-2)(x+3)=0 and one of the root is 2

= x²+3x-2x-6=0

x²+x-6=0

x²+3x-2x-6=0

x(x+3) -2(x+3)=0

(x-2)(x+3)=0

x-2=0,. x+3=0

x=2,. x= -3

therefore the another root of give n equation is -3