Question

If one root of equation is x2

– kx + 12 = 0 is 3, then find k.​

Answer 1

Answer:

x²-kx +12=0

3²-k3+12=0

9-3k+12=0

21-3k=0

21=3k

21/3=k

7=k

Answer 2

Answer:

Hey mate here's your answer...

• If one root is 3 then...
• x2-kx+12=0

x ni jagyaae 3 naakhi de... So...

• (3)^2 - k(3) + 12 = 0
• 9 - 3k +12=0
• 3k= 12+9
• 3k=21

k=7.

Hope this helps you....

All the best for boards...

Baaki dp mast chhe huh.... ❤️❤️

Yours sincerely

Jalay