Question

if one root of equation x²-4x+3=0 is also the root of x²-6x+k =0 then k=​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

x² - 4x + 3

x² -3x -1x +3

x(x -3) -1(x-3)

(x-3)(x-1)

x=3,1.

roots of equation are 3,1.

x² -6x + k

if u keep k=5

x² -6x + 5

x² -5x -1x + 5

x(x-5) -1(x-5)

(x-1)(x-5)

x=1,5

then roots for that equation are 1,5.