Question

if one root of equation x2+ax+3=0is 1 theb its other root is​

Answer 1

if one root is 1 then

1+a+3=0

a=-4

${x}^{2} - 4x + 3 = 0$

${x}^{2} - x - 3x + 3 = 0$

$x(x - 1) - 3(x - 1) = 0$

$(x - 3)(x - 1) = 0$

so, Second root is 3..

Answer 2

Explanation:

sum of roots = -a

product of roots = 3

let p,1 be the roots of the given equation,

now, p(1) = 3

p= 3

p+1 = -a

3+1 = -a

a = -4

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