Question

if one root of equation x2+px+12=0is4 while the equation x2+px+q=0has equal roots the value of Q is ​

Answer 1

Answer:

let @ be 2nd root of X2+px+12=0

we know

@+£=-b/a ( here £ is one root which is 4 given in question)

@£=c/a

so

@+4=-p/1 -(1)

@*4=12 =@=12/4=3.

so from 1 , -p=3+4=7

p=-7 --(2)

and in 2nd equation it have equal roots so discriminant equal to zero.

b2-4ac=0

p2-4q=0

p2=4q

from (2)

4q=(-7)^2

4q=49

q=49/4=12.25

I hope it will help you.

thank you for asking.