Question

if one root of equations x^2-3x+k=0 is 2 .find k​

Answer 1

Answer :

$x {}^{2} - 3x + k = 0 \\ (2) {}^{2} - 3(2) + k = 0 \\ 4 - 6 + k = 0 \\ - 2 + k = 0 \\ k = 2$

Answer 2

Answer:

x²-3x+k=0

2²-3*2+k=0

4-6+k=0

-2+k=0

k=2