Math, asked by rajkumarjovi, 5 months ago

if one root of px^2-qx+r=0 is square of the other then the condition

Answers

Answered by Anonymous
16

Answer:

let α,β be roots of given eq^n then

(α+β)=(−q/p) & αβ=(r/p),(α=3β)

⇒4β = −q/p

⇒ 16β² = q² /p² and 3β² =r/p

⇒β2=( \frac{r}{3p} )

16( \frac{r}{3p} )

= \frac{ {q}^{2} }{ {p}^{2} }  \boxed{⇒3q2=16pr }

Similar questions