if one root of px2 +q X + r=0 exceeds other route by k find the relation among P q rand K
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the roots are (-q+✓[q^2-4pr])/2p and (-q-✓[q^2-4pr])/2p
so the difference is 2×✓(q^2-4pr)
which is equivalent to k
so , squaring both sides
4×(q^2-4pr)=k^2
so the difference is 2×✓(q^2-4pr)
which is equivalent to k
so , squaring both sides
4×(q^2-4pr)=k^2
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