Question

If one root of quadratic equation 2x^2+kx-6=0 is 2, find the value of K also find the other root?

Answer 1

Answer:

Here, The value of k is (-1) and the other root is(-3)/2.

Step-by-step explanation:

Here, As per our question,

=p(x)=2x^2+kx-6=0

Given root of the equation is=2.

Now, As 2 is a root of the equation, put the value of 2 in the place of x in equation to get the value of k,

=2(2)^2+k(2)-6=0

=8+2k-6=0

=2k+2=0

=2k=(-2)

=k=(-2)/2

=k=(-1)

Now, As the value of k is (-1), Put the value of k in the equation to obtain other root,

=2(x)^2+(-1)x-6=0

=2x^2-x-6=0

Now, On factorizing the equation by splitting of middle term, we get,

=2x^2-4x+3x-6=0

On taking common in it, we get,

=2x(x-2)+3(x-2)=0

Now Again taking common in it, we get,

=(2x+3) , (x-2)

=2x+3=0 , x-2=0

=2x=(-3) , x=2

=x=(-3)/2

Hence, the other root in this equation is (-3)/2.

Thank you.