if one root of quadratic equation 2x2 + Kx - 6 = 0 is 2 fins value of K
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Answered by
0
Step-by-step explanation:
A/Q, x=2
so,
=2×2+2k-6=0
=4+2k-6=0
=2k=2
=k=1
Answered by
1
Step-by-step explanation:
Since x=2 is a root of the equation
2x² + kx − 6 = 0
2k+2=0
k=−1
Putting k =-1 in the given equation, we get,
2x² − x − 6 = 0
(x−2)(2x+3) = 0
x=2, -3
2
Hence, the other root is −3.
2
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