Question

if one root of quadratic equation is 1-√3 then other root us?​

Answer 1

Answer:

$quadratic \: eq. \: roots \: are \: \: \\ sum \: of \: zeros \: \\ and \\ \: product \: of \: zeros \: \\ let \: \: 1 - \sqrt{3} \: \: be \: sum \: of \: zeros \\ sum \: of \: zeros \: = \\ - \frac{b}{a} = 1 - \sqrt{3} \\ - b \: = a(1 - \sqrt{3} ) \\ b \: = - a(1 - \sqrt{3} ) \\ product \: of \: zeros \: = \\ \frac{c}{a} =$

Answer 2

Answer:

The other root of equation is

$1 + \sqrt{3}$

Step-by-step explanation:

Given that,

One root of a quadratic equation is

$x _{1} = 1 - \sqrt{3}$

To find the other root of the quadratic equation,we have a known theorem which is stated below.

For a quadratic equation,if the determinant of the equation is positive,then the roots exits in conjugate pairs as follows

$roots = a + \sqrt{b} \: and \: a - \sqrt{b}$

Based on this,the other root of given equation is found as below

$x _{2} = 1 + \sqrt{3}$

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