If one root of quadratic equation x^2-8x+k=0 is 4+root3.find value of k
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Answer:
One of the root of the equation is h+2
6
, then the other is h−2
6
Sum of the roots =h+2
6
+h−2
6
=6
2h=6⇒h=3
Product of the roots =(h+2
6
)(h−2
6
)=k
h
2
−(2
6
)
2
=k
9−24=k
⇒k=−15
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