If one root of quadratic equation x2-11x +k =0 is 9.find the value of k.
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let the other root be y
therefore two roots will be 9 and y
as the roots sum should be equal to - b/a
therefore 9 + y= -(-11)/1
therefore y = 2
and also the product of roots is equal to c/a
therefore (9)(2) = k/1
therefore k = 18
therefore two roots will be 9 and y
as the roots sum should be equal to - b/a
therefore 9 + y= -(-11)/1
therefore y = 2
and also the product of roots is equal to c/a
therefore (9)(2) = k/1
therefore k = 18
sriram77:
ur welcome
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x^2-11x+k=0
(9)^2-11(9)+k=0. {One root of equation is 9}
81-99+k=0
k=18
(9)^2-11(9)+k=0. {One root of equation is 9}
81-99+k=0
k=18
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