if one root of quadratic equation x² + 5x- k=0 is -3 find the other root and value ok k
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x'2 + 5x - k = 0 and x=-3
=> (-3)'2 + 5(-3) - k = 0
=> 9-15-k=0
=>-6-k=0
=> k=-6
x'2 + 5x -(-6) = 0
x'2 + 5x + 6 = 0
x'2 + 2x + 3x + 6 = 0
x(x+2)+3(x+2)=0
x+3=0 or x+2 =0
x=-3 or -2
the symbol ' represents power
=> (-3)'2 + 5(-3) - k = 0
=> 9-15-k=0
=>-6-k=0
=> k=-6
x'2 + 5x -(-6) = 0
x'2 + 5x + 6 = 0
x'2 + 2x + 3x + 6 = 0
x(x+2)+3(x+2)=0
x+3=0 or x+2 =0
x=-3 or -2
the symbol ' represents power
Sarfaraz786:
thanks
can you say x= -3 or 3
how u can say x=3 ?
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