Question

If one root of quadratic equations 2x²+Kx -6 =0 is 2 .find value of k. Also find other root

Answer 1

Step-by-step explanation:

on substituting x=2 in the equation, we get,

2(2)^2+k(2)-6=0

8-6+2k=0

2+2k=0

2k= -2

k=-1

2x^2-x-6=0

2x^2-4x+3x-6=0

2x(x-2)+3(x-2)=0

(x-2)(2x+3)=0

other root is -3/2

Answer 2

Step-by-step explanation:

2x^2 + Kx - 6 = 0

x = 2

2(2)^2 + K(2) -6 = 0

2(4) + 2K - 6 = 0

8 + 2K - 6 = 0

2K = 0-8+6

2K = -2

K = -2/2

K = -1