Question

if one root of quadratic polynomial is 2+root 3 then other root is

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Answer 1

Answer:

\begin{gathered}2 {x}^{2} - 3x + p \\ 2( {3})^{2} - 3(3) + p = 0 \\ 18 - 9 + p = 0 \\ p = - 9 \\ 2 {x}^{2} - 3x - 9 = 0 \\ 2 {x}^{2} - 6x + 3x - 9 = 0 \\ 2x(x - 3) + 3(x - 3) = 0 \\ (x - 3)(2x + 3) = 0 \\ 2x + 3 = 0 \\ x = \frac{ - 3}{2} \\\end{gathered}

2x

2

−3x+p

2(3)

2

−3(3)+p=0

18−9+p=0

p=−9

2x

2

−3x−9=0

2x

2

−6x+3x−9=0

2x(x−3)+3(x−3)=0

(x−3)(2x+3)=0

2x+3=0

x=

2

−3

another root is -3/2, p= -9