If one root of the cubic polynomial x3+ax2+bx+c is -1, then the product of the other two zeros is
(a) b-a+1
(b) b-a-1
(c) a-b+1
(d) a-b-1
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Step-by-step explanation:
product of the other two zeros is
(a) b-a+1
(b) b-a-1
(c) a-b+1
(d) a-b-1product of the other two zeros is
(a) b-a+1
(b) b-a-1
(c) a-b+1
(d) a-b-1hfokproduct of the other two zeros is
(a) b-a+1
(b) b-a-1
(c) a-b+1
(d) a-b-1ytog5fproduct of the other two zeros is
(a) b-a+1
(b) b-a-1 product of the other two zeros is
(a) b-a+1
(b) b-a-1
(c) a-b+1product of the other two zeros is
(a) b-a+1
(b) b-a-1
(c) a-b+1
(d) a-b-1jjfo
(d) a-b-1
(c) a-b+1
(d) a-b-1
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