Question

if one root of the equation 2x^2+3x-k =0 is 6 what is the value of k?

Answer 1

Answer:

90

Step-by-step explanation-

Given-

6 is zero of the polynomial

So now replace x by 6

2x²+ 3x -k=0

2(6)² + 3(6) - k =0

2(36) + 18 - k =0

K = 72 +18

K = 90

Thus value of k is 90

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Mark as brainliest ❤️

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