If one root of the equation 2x² -10+p = 0 , is 2 then, find the value of p
Answers
Answered by
1
2x^2-10+p=0
2(2)^2-10+p=0
2(4)-10+p=0
8-10+p=0
-2+p=0
p=2
2(2)^2-10+p=0
2(4)-10+p=0
8-10+p=0
-2+p=0
p=2
Answered by
1
Sum of roots
2+p= -b/a
2+p=10/2
2+p=5
Therefore
p=3
Similar questions