If one root of the equation 3x^2+ax+2=0 is -2, find the value of a and the other root
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Answered by
1
Answer:
p(x)=3x2+ax+2
p(-2)=0
3(-2)^2-2a+2=0
-2a=-14
a=7
p(x) = 3x2+7x+2
3x2+6x+x+2
3x(x+2)+1(x+2)
(x+2)(3x+1)
x+2=0 or 3x-1=0
x=-2 or x= 1/3
other root is 1/3.
I hope this helps!
Answered by
0
Answer:
a=7
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