Question

if one root of the equation 3x^2-kx-2=0 is 2 find the value of k also find the other root

Answer 1

Step-by-step explanation:

given : x=2 (root=2)

$3 {x}^{2} - kx - 2 = 0$

$3( {2)}^{2} - k(2) - 2 = 0$

$3(4) - 2k - 2 = 0$

$12 - 2 - 2k = 0$

$10 - 2k = 0$

$2k = 10$

$k = \frac{10}{2}$

$k = 5$

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