Question

If one root of the equation 3y^2+ky+81=0,is th square the other then find k

Answer 1

Answer:

k = -36

Step-by-step explanation:

let the roots be u and u²

product of the roots = c/a = 81/3= 27

i.e. u * u² = u³ = 27

u = 3

sum of the roots = -b/a = -k/3

Also u + u² = 3+9 = 12

that is -k/3 = 12 then k= -36