If one root of the equation ax^2+bx+c=0 is three times the other ,then b^2:ac::
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LET TWO ROOT OF EQUATION ARE d band 3d
then according to ques,
sum of root=>
d+3d=-b/a
solving this we get
4d=-b/a..........eqn 1
and product of root
3d^2=c/a..........eqn 2
putting value of d from eqn 1 into 2 we get
3b^2/16a=c
so 3b^2=16ac
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