Question

If one root of the equation ax2 - 7x + 12 = 0 is 3, then find value of a​

Answer 1

hope it help u btw thnks for giving a short

Answer 2

Answer:

k=1

Step-by-step explanation:

The given quadratic equation kx^2 -7x +12=0

let a and b be the roots of the given equation

comparing the given equation with the standard equation

ax^2 +bx +c =0

a=k, b=-7 ,c=12

Thus,

a+ b = -b/a = -7/k

and ab = c/a = 12/k

since one the root is 3,

3 +b = 7/k and 3b =12/k

3 +b = 7/k and b = 4/k

substitution the value of b =4/k

3 + 4/k = 7/k

3k + 4/k = 7/k

3k + 4 = 7

3k = 7 - 4

3k = 3

k = 3/3

k= 1