Question

If one root of the equation ax² + bx + c =0 is reciprocal of the
one root of the equation a₁x²+ b₁x + c₁ = 0, then
(a) (aa₁ - cc₁)² = (bc₁ - b₁a) (b₁c - a₁b)
(b) (ab₁ - a₁b)² = (bc₁ - b₁c) (ca₁ - c₁a)
(c) (bc₁ - b₁c)² = (ca₁ - a₁c) (ab₁ - a₁b)
(d) none of these

Answer 1

Answer:

option is B ...........