Math, asked by stonerawm, 8 months ago

if one root of the equation ax²+bx+c=0 is the cube of the other, prove that,(b²-2ac)²=ca(c+a)²​

Answers

Answered by Anonymous
2

Step-by-step explanation:

What would you like to ask?

10th

Maths

Quadratic Equations

Nature of Roots

If one root of the equation...

MATHS

avatar

Asked on December 30, 2019 by

Zilvi Sindhu

If one root of the equation ax

2

+bx+c=0;a,b,c∈R is cube of other, then

a+c

b

2

−2ac

is equal to

HARD

Share

Study later

ANSWER

Let the roots be α and α

3

∴α+α

3

=−

a

b

and α

4

=

a

c

⇒α

2

(1+α

2

)

2

=

a

2

b

2

⇒α

2

+2α

4

6

=

a

2

b

2

a

c

+

a

2c

+

a

c

a

c

=

a

2

b

2

a

c

(1+

a

c

)=

a

2

b

2

−2ac

a

c

(

a

a+c

)

2

=

a

4

(b

2

−2ac)

2

⇒ac=(

a+c

b

2

−2ac

)

2

a+c

b

2

−2ac

ac

Similar questions