Question

If one root of the equation (k-1)x^2-10x+3=0 is the reciprocal of the other ,then the value of k is ?​

Answer 1

Answer:

plzzz give me brainliest ans and plzzzz follow me

Answer 2

Answer:

k= 4

Step-by-step explanation:

Given : (k-1)$x^{2}$ - 10x +3 =0

Here , a = k-1

           b = -10

           c = 3

Product of roots, α and β is

αβ = $\frac{c}{a}$

αβ = $\frac{3}{k-1}$ -------------- (i)

we know that,

α=$\frac{1}{\beta }$  or αβ = 1 ------------ (ii)

Comparing (i) and (ii) ,

αβ = $\frac{3}{k-1}$ =1

3 = k-1 or k = 3+1 = 4

Hence k = 4