Question

If one root of the equation px^2-14x+8=0 is six times the other, then find the value of p.

Answer 1

if α,β be root s of equation then
px^2-14x+8=0
one root of the equation px^2-14x+8=0 is six times the other
then sum  of roots of equation =14/p
α=6β
β+6β=14/p
7β=14/p
β=2/p
product of roots =8/p
6β^2=8/p
6(4/p^2)=8/p
3/p^2=1/p
p^2-3p=0
p=0   p=3

Answer 2

the above attachment will give you the answer
hope you have understood
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