Question

If one root of the equation px2-(2p+3)x-(p+1)=0 be 3,find p and also other root​

Answer 1

Answer:

P=-5 other root=-3/5

Step-by-step explanation:

px2-(2p+3)-(p+1)=0

p(3)^2-(2p+3)3-(p+1)=0

9p-6p+9-p+1=0

3p-p+10=0

2p=-10

p=-10/2

p=-5

Now, we got p value. So substitute p value in the equation.

5x^2-(10+3)x-6=0

5x^2-13x-6=0

5x(x-2)+3(x-2)

5x+3=0

x=-3/5