Question

If one root of the equation x^2 - 3x + k =0 is 2, then value of k will be
(A) - 10
(B) O
(C) 2
(D) 10

I think answer is 2, but not sure
anyone ????​

Answer 1

Answer:

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Answer 2

The correct answer is option (C) 2.

Given:

A quadratic equation x²-3x+k = 0.

One of the roots of the given equation is 2.

To Find:

The value of k.

Solution:

A quadratic equation is an equation in one variable with degree 2.

The general form of a quadratic equation is ax²+bx+c = 0.

The zeros or roots of any polynomial p(x) are those values of x for which the value of the polynomial becomes zero, i.e. p(x) = 0.

A polynomial with degree 'n' has exactly n zeros.

Now, we are given a quadratic equation x²-3x+k = 0.

It is given that one of the roots of the given equation is 2.

This means that on substituting x=2, the value of the polynomial becomes zero.

On substituting x=2 we get:

2² - 3(2) + k = 0

⇒ 4 - 6 + k = 0

⇒ k = 2.

∴ The value of k is 2.

Hence, the correct answer is option (C) 2.

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