If one root of
the equation X^2+ax+3=0 is 1 then find
its other root.
Answers
Answered by
9
Answer:
the other root is = +3
Step-by-step explanation:
since 1 is a root of the equation,
putting x=1 in the equation, we get the result to be 0
1^2 + a*1 + 3 =0
1+a+3=0
a=-4
therefore, the original equation is x^2 - 4x +3 = 0
now middle term factorizing it we get
x^2 - 3x - x +3=0
x(x-3)-1(x-3)=0
(x-3)(x-1)=0
either x = 3 or, x = 1
therefore, the other root for the equation is 3
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