Question

If one root of the equation (x-4) (x+3) =0 is 4 then find the another root of the equation.​

Answer 1

Answer:

its -3

Step-by-step explanation:

the equation is already factorized

if the value of x-4 becomes 0 then it's a root of the equation therefore one root us 4

and if the value of x+3 becomes 0 then it's a root of the equation therefore the 2nd root if -3

Answer 2

(x-4) (x+3) =0

x² +3x-4x -12 =0

x² -x -12 =0

let the missing roots be y

then

here product of roots = c/a =

-12 = 4×y

y= -12/4

y= -3