if one root of the equation :X sq.- 8 x + m = 0 exceed the other by 4,then the value of m is
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Two root's are a & a + 4
Then sum of roots ( a + a + 4)= - b/a = 8
2a= 8-4
a = 2
Products of roots a x (a + 4) = c/a = m
M = 2( 2 + 4) = 12
Then sum of roots ( a + a + 4)= - b/a = 8
2a= 8-4
a = 2
Products of roots a x (a + 4) = c/a = m
M = 2( 2 + 4) = 12
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