Question

if one root of the equation x2-19x+88=0 be 8,what will be the other root?​

Answer 1

Answer:

11

Step-by-step explanation:

product of roots = c/a

8 × root = 88/1

root = 88/8

root = 11

Answer 2

The roots of equation are x = 8 and x = 11

Solution:

Given equation is:

$x^2 - 19x+88=0$

We have to find the roots of equation

From given,

$x^2 - 19x+88=0\\\\Split\ the\ middle\ term\\\\x^2-8x-11x + 88 = 0\\\\\mathrm{Break\:the\:expression\:into\:groups}\\\\\left(x^2-8x\right)+\left(-11x+88\right) = 0\\\\\mathrm{Factor\:out\:}x\mathrm{\:from\:}x^2-8x\mathrm{:\quad }\\\\x(x - 8) + (-11x + 88) = 0\\\\\mathrm{Factor\:out\:}-11\mathrm{\:from\:}-11x+88\mathrm{:\quad }\\\\x(x-8) -11(x - 8) = 0\\\\\mathrm{Factor\:out\:common\:term\:}x-8\\\\\left(x-8\right)\left(x-11\right) = 0\\\\Thus\ the\ roots\ are\\\\x = 8\\\\x = 11$

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