If one root of the equation x² - 3x + q = 0 is twice the other. Then the value of q is
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Answer:
q=2
Step-by-step explanation:
p(x) = x² - 3x + q = 0
Let α=2β
then,
α+β = -b/a
2β+β = -(-3)/1
3β = 3
β = 1
Now that we have found one root of p(x), we'll substitute in it.
p(x) = x² - 3x + q = 0
⇒ (1)² - 3(1) + q = 0
⇒ 1- 3 + q = 0
⇒ -2 + q = 0
∴ q = 2
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