If one root of the equation x²-4x-12=0 is 6,
find the other root
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x²−4x+k=0
has two roots:
√2±4−k
if one of them is 6 than
2±√4−k = 6∣−2
±√4−k=4∣y²
4−k=16∣−4
−k=12∣÷−1
k=−12
Also note the other root is −2:
x²−4x−12=(x−6)(x+2)
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