Question

If one root of the equation x²-6kx+5=0 is 5 then the other root and k will respectively be​

Answer 1

Answer:

k=1

Step-by-step explanation:

Given, one root of x2 - 6kx + 5 = 0 is 5.

∴ x = 5 satisfies x2 - 6kx + 5 = 0

⇒ 52 - 30k + 5 = 0

⇒ 25 - 30k + 5 = 0

⇒ 30 - 30k = 0

⇒ 30k = 30

∴ k = 1

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Answer 2

Answer:

K = 1 and Other root = 1

Step-by-step explanation:

One root of the equation $x^{2} -6kx+5=0$ is 5, i.e. 5 must satisfy the equation.

⇒ $5^2-(6)(5)(k)+5=0$

⇒ $30-30k=0$

⇒ k = 1

Therefore the equation will be $x^{2} -6x+5=0$

⇒ $x^{2} -5x-x+5=0$

⇒ $x(x-5)-1(x-5)=0$

⇒ $(x-1)(x-5)=0$

⇒ $x=1,5$

Therefore the other root is 1 and value of k is also 1.