Question

IF one root of the equation x2 - 6x + 2p = 0 is 2, then find the value of p.​

Answer 1

Answer:

Answer is :

Step-by-step explanation:

x²-6x+2p =0

(2)²-6×2+2p =0

4-12 +2p =0

-8 + 2p =0

2p = 8

p= 8/2

p = 4

Answer 2

Answer:

Given: x²-6x+2p=0

and one root as 2 then

p(x)= x²-6x+2p

p(2) = (2) - 6(2) + 2(2)

= 4 - 12 +4

= 4 - 16

= -14