Question

If one root of the equation x² + px+ 12 = 0 is 4, while equation x2 + px + q =0 has equal roots then the
value of q is
​

Answer 1

Answer:

q= 49/4

Step-by-step explanation:

p(x) = x^2+px+12=0 since 4 is a root,p(4) = 16+4p+12=0⇒ p =-7

in substituting the value of p in the eq. x^2+px+q=0, and by using the rule b^2-4ac =0( given that roots are equal) we get q=49/4