if one root of the equation x²+px+ q=0 if 3 times the other than prove yhat 3p²=16 q
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Answer:
Step-by-step explanation:
Let the zeroes of equation are a and b
According to question
a=3b
Sum of zeroes=
-coefficient of x/coefficient of x²
a+b = -p/1
3b+b = -p
4b= -p
b= -p/4 ---------1
Product of zeroes=
constant/coefficient of x²
a×b = q/1
3b×b = q
3b² = q
Put value of b
3(-p/4)²=q
3(p²/16)=q
3p²=16q
Hence proved
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