If one root of the equation x²+px+q=0 is 4 times of the other root,then: a)p²-4q=0. b)4p²=q² c)25p²=4q. d)4p²=25q
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Let the roots of this equation be 'a' &'4a'.Then,
a+4a= -p
i-e, 5a= -p
Also,
a×4a = q
i-e,4a^2=q
Now,
4p^2=4×(5a)^2
=100a^2
25q=25×4a^2
=100a^2
So,4p^2=25q
Hence,option D is the correct choice.
Hope it helps.
a+4a= -p
i-e, 5a= -p
Also,
a×4a = q
i-e,4a^2=q
Now,
4p^2=4×(5a)^2
=100a^2
25q=25×4a^2
=100a^2
So,4p^2=25q
Hence,option D is the correct choice.
Hope it helps.
Adeeba123:
I am really glad the answer helped..:-)
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