Math, asked by Hrishu1, 1 year ago

If one root of the equation x⁴+x²+1=0 is α the others are -α and ±α².(Show)

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hhugx: hi

Answers

Answered by saurabhsemalti
0
let
 {x}^{2}  = t \\ eqn \: becomes \\ 1 + t +  {t}^{2}  = 0 \\ apply \: quad \: formula \:  \\ although \: it \: will \: give \: cube \: root \: of \: unity \: but \: still \\ t =  \frac{ - 1( +  - ) \sqrt{1 - 4} }{2}  \\ t = ( \frac{ - 1}{2} ) + ( \frac{ \sqrt{3} }{2} ) \\ ad \:  \\ t = ( \frac{ -1 }{2} )  -  ( \frac{ \sqrt{3} }{2} )
check these are cube roots of unity
also the given eqn is satisfied by
cube roots of unity

Hrishu1: I haven't understood your solution.
Hrishu1: I told to show
saurabhsemalti: let the answer be deleted then I'll repost
saurabhsemalti: this eqn has complex roots, I. e., w and w^2,,,,,which are cube roots.... if u know abt complex......these points form triangle in quadrant........... quadratic formula is applied and u can check their dependence on each other by putting in eqn
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