Question

If one root of the quadratic equation 2x^2+3x+p=0 is 3 then find the value of p and other root

Answer 1

Answer:

Step-by-step explanation:

Given 2x 2+3x+p=0

One root is 3

So x=3

2*3*3+3*3+p=0

18+9+p=0

p=-27

We know

Alpha +beta =-b/a

That is alpha =3

3+beta =-3/2

Beta =- 3/2-3

=- 3-6/2

= - 9/2

So other root is -9/2