Question

if one root of the quadratic equation 2x^2+kx-6=0 is 2. find the value of k. also,find the other root.
solve in brief please
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Answer 1

Answer:

2x² + kx - 6 = 0

2 × 2² + k × 2 - 6 = 0

8 + 2k - 6 = 0

2 + 2k = 0  

2k = -2

k = -2/2

  = -1

The roots are 2 & (-1)

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Answer 2

Step-by-step explanation:

As x=2

p(x) =2x^2+kx-6

p(2)=2(2^2)+k(2)-6

2(4)+2k-6=0

8+2k-6=0

2k+2=0

2k=-2

k=-2/2=-1

hence value of k is -1 .

the product of the two roots of the quadratic equation is c/a.

a=2 & b=? ( could not find alpha and beta on

keypad so took it as a & b)

ab =c/a

2b =-6/2

2b=-3

b=-3/2

Hence, other root is -3/2.

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