Question

If one root of the quadratic equation 2x^2+kx-6=0 is 2 then find the value of k+1

Answer 1

HELLO DEAR,


GIVEN THAT:-


x = 2 put the values in Equation,

we get,

2(2)² + k(2) - 6 = 0

⇒8 + 2k - 6 = 0

⇒2k = -2

⇒k = -1


NOW,


K + 1 = -1 + 1 = 0



I HOPE ITS HELP YOU DEAR,
THANKS

Answer 2

Given that one root is 2,

So, x = 2 

Putting the value of x in the given equation,

⇒$2x^2 + kx -6 = 0$

⇒$2(2)^2 + k(2) = 6$

⇒(2 × 4) + 2k = 6

⇒8 + 2k = 6

⇒2k = 6 - 8 

⇒2k = -2 

⇒$k = \frac{-2}{2}$

⇒k = -1 

============================

Then,

k +1 

⇒-1 + 1 

⇒0


i hope this will help you


-by ABHAY