Question

If one root of the quadratic equation 2x^2+kx-6=0 is 2 then find the value of k

Answer 1

hey..

2x^2 + k(2) - 6 = 0
2(2)^2 + 2k - 6 = 0
2(4) + 2k - 6 = 0
8 + 2k - 6 = 0
2 + 2k = 0
2k = -2
k = -2/2
k = -1

Answer 2

HERE IS YOUR ANSWER MATE


2X^2+Kx-6=0

2(2)^2+K(2)-6=0

2(4)+2K-6=0

8+2k-6=0

2K+2=0

2K=-2

K=-2/2

K=-1

HOPE IT HELPS YOU

PLZZ MARK BRAINLIEST