If one root of the quadratic equation 2x^2+kx-6=0 is 2 then fin find the value of kI
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Answer:
K = -1
Step-by-step explanation:
2x^2 + kx -6 = 0
x = 2
2*(2)^2 + 2k -6 = 0
8 + 2k - 6 = 0
2k = -2
k = -1
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The attached image will help you ^^
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amitnrw:
why did u make solution so complex ?
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